Sarlikaran question – सरलीकरण के 51 महत्वपूर्ण सवाल

Q31. b – [b – (a + b) – {b – (b – a – b)} + 2a] सरल कीजिए ?

= b – [b – (a + b) – {b – b + a + b} + 2a]
= b – [b – a – b – a – b + 2a]
= b – b
= 0

Q32. यदि \frac{256}{0.256} = \frac{25.6}{x} है तो x का मान क्या होगा ?

\frac{256000}{256} = \frac{256}{10x}
10x = \frac{256×256}{256000}
10x = 0.256
x = 0.0256

Q33. \frac{7|2 - 6|- 4|5| ÷ 5}{-7(2) - 2×2 ÷ 2 + 2}

= \frac{7|- 4|- 4(1)}{-14 - 2×(1) + 2}
= \frac{28 - 4}{-14 - 2 + 2}
= \frac{28 - 4}{-14 - 2 + 2}
= \frac{24}{-14}
= \frac{12}{-7}

Q34. \frac{675×675×675 + 325×325×325}{67.5×67.5 + 32.5×32.5 - 67.5×32.5}

माना a = 67.5 और b = 32.5

= 1000(a3 + b3) / (a2 + b2 – ab)
= 1000(a + b)(a2 + b2 – ab) / (a2 + b2 – ab)
= 1000(a + b)

= 1000000

Q35. 9 \frac{3}{4} ÷ [2 \frac{1}{6} + {4 \frac{1}{3} – (2 \frac{1}{2} + \frac{3}{4} )}]

= \frac{39}{4} ÷ [ \frac{13}{6} + { \frac{13}{3} – ( \frac{5}{2} + \frac{3}{4} )}]
= \frac{39}{4} ÷ \frac{26+52-30-9}{12}
= \frac{39}{4} ÷ \frac{39}{12}
= \frac{39}{4} × \frac{12}{39}
= 3

Q36. 4 \frac{4}{5} ÷ \frac{3}{7} का 7 + \frac{4}{5} × \frac{3}{10} \frac{1}{5}

= \frac{24}{5} ÷ \frac{3}{7} × 7 + \frac{4}{5} × \frac{3}{10} \frac{1}{5} {By using BODMAS rule}
= \frac{24}{5} ÷ 3 + \frac{12}{50} \frac{1}{5}
= \frac{24}{5} × \frac{1}{3} + \frac{12}{50} \frac{1}{5}
= \frac{8}{5} + \frac{1}{25}
= \frac{41}{25}

Q37. \frac{6.75×6.75×6.75 - 4.25×4.25×4.25}{67.5×67.5 + 42.5×42.5+67.5×42.5}

माना a = 6.75 और b = 4.25

= (a3 – b3) / 100(a2 + b2 + ab)
= (a – b)(a2 + b2 + ab) / 100(a2 + b2 + ab) {∵ using formula of (a3 – b3)}

= (a – b) / 100

= 0.025

Q38. 5 \frac{1}{5} – [3 \frac{1}{2} – { \frac{5}{6} – ( \frac{3}{5} + \frac{1}{10} \frac{4}{15} )}]

= \frac{26}{5} – [ \frac{7}{2} – { \frac{5}{6} – ( \frac{3}{5} + \frac{1}{10} \frac{4}{15} )}]
= \frac{26}{5} – [ \frac{7}{2} – { \frac{5}{6} – ( \frac{7}{10} \frac{4}{15} )}]
= \frac{26}{5} – [ \frac{7}{2} – { \frac{5}{6} – ( \frac{13}{30} )}]
= \frac{26}{5} – [ \frac{7}{2} \frac{12}{30} ]
= \frac{26}{5} - \frac{93}{30}
= \frac{63}{30}

Q39. [3 \frac{2}{3} - { \frac{15}{4} (5 \frac{4}{5} ÷ 14 \frac{1}{2} )}]

= [ \frac{11}{3} – { \frac{15}{4} ( \frac{29}{5} ÷ \frac{29}{2} )}]
= [ \frac{11}{3} – { \frac{15}{4} ( \frac{29}{5} × \frac{2}{29} )}]
= [ \frac{11}{3} – { \frac{3}{2} }]
= \frac{13}{6}

Q40. 5 ÷ 5 का 5 × 2 + 2 ÷ 2 का 2 × 5 – (5 – 2) ÷ 6 × 2 का मान है

= 5 ÷ 5 × 5 × 2 + 2 ÷ 2 × 2 × 5 – (5 – 2) ÷ 6 × 2 {∵ BODMAS rule}
= 5 ÷ 25 × 2 + 2 ÷ 4 × 5 – (5 – 2) ÷ 6 × 2
= \frac{1}{5} × 2 + \frac{1}{2} × 5 – (3) ÷ 6 × 2
= \frac{1}{5} × 2 + \frac{1}{2} × 5 – \frac{1}{2} × 2
= \frac{2}{5} + \frac{5}{2} \frac{2}{2}
= \frac{29}{10} \frac{2}{2}
= \frac{19}{10}

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